Math  /  Data & Statistics

QuestionThe stock prices for eight major grocery store chains last January were: \begin{tabular}{llllllll} $18.28\$ 18.28 & $20.32\$ 20.32 & $9.36\$ 9.36 & $11.55\$ 11.55 & $11.23\$ 11.23 & $48.06\$ 48.06 & $48.84\$ 48.84 & $28.23\$ 28.23 \end{tabular} Send data to Excel
Find the range, variance, and standard deviation. Round the variance to one decimal place and the standard deviation to two decimal places, if necessary.
Part: 0/30 / 3
Part 1 of 3
The range is $\$ \square .

Studdy Solution

STEP 1

1. The set contains eight stock prices: 18.28,20.32,9.36,11.55,11.23,48.06,48.84,28.23 18.28, 20.32, 9.36, 11.55, 11.23, 48.06, 48.84, 28.23 .
2. The range is the difference between the maximum and minimum values in the data set.

STEP 2

1. Identify the minimum and maximum values.
2. Calculate the range.

STEP 3

List the stock prices:
18.28,20.32,9.36,11.55,11.23,48.06,48.84,28.23 18.28, 20.32, 9.36, 11.55, 11.23, 48.06, 48.84, 28.23

STEP 4

Identify the minimum value:
Minimum=9.36 \text{Minimum} = 9.36
Identify the maximum value:
Maximum=48.84 \text{Maximum} = 48.84

STEP 5

Calculate the range:
Range=MaximumMinimum=48.849.36=39.48 \text{Range} = \text{Maximum} - \text{Minimum} = 48.84 - 9.36 = 39.48
The range is:
39.48 \boxed{39.48}

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