Math  /  Data & Statistics

QuestionThe table shows the probability distribution for a discrete random variable XX. a. Complete the table by finding the missing values of xP(x)x \cdot P(x). Then compute the mean of the probability distribution. \begin{tabular}{|r|r|r|} \hlinexx & P(x)P(x) & xP(x)x \cdot P(x) \\ \hline 3 & 0.19 & \\ \hline 4 & 0.2 & 0.8 \\ \hline 5 & 0.37 & \\ \hline 6 & 0.24 & 1.44 \\ \hline \end{tabular} μX=4.66\mu_{X}=4.66

Studdy Solution

STEP 1

1. The table provides a probability distribution for a discrete random variable X X .
2. The mean of the probability distribution is denoted by μX \mu_X .

STEP 2

1. Complete the table by calculating the missing values of xP(x) x \cdot P(x) .
2. Compute the mean of the probability distribution using the completed table.

STEP 3

Calculate the missing value for x=3 x = 3 :
xP(x)=30.19=0.57 x \cdot P(x) = 3 \cdot 0.19 = 0.57

STEP 4

Calculate the missing value for x=5 x = 5 :
xP(x)=50.37=1.85 x \cdot P(x) = 5 \cdot 0.37 = 1.85

STEP 5

Sum the values of xP(x) x \cdot P(x) to find the mean:
μX=0.57+0.8+1.85+1.44 \mu_X = 0.57 + 0.8 + 1.85 + 1.44

STEP 6

Compute the sum:
μX=4.66 \mu_X = 4.66
The completed table and mean are:
\begin{tabular}{|r|r|r|} \hline x & P(x) & x \cdot P(x) \\ \hline 3 & 0.19 & 0.57 \\ \hline 4 & 0.2 & 0.8 \\ \hline 5 & 0.37 & 1.85 \\ \hline 6 & 0.24 & 1.44 \\ \hline \end{tabular}
The mean of the probability distribution is:
μX=4.66 \mu_X = 4.66

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