Math

QuestionTotal cost for ff friends bowling for hh hours is: C=5f+45hC = 5f + 45h.

Studdy Solution

STEP 1

Assumptions1. The cost of shoe rentals per player is 5.Thecostofbookingalaneperhouris5. The cost of booking a lane per hour is 453. The number of friends going bowling is represented by ff
4. The number of hours they go bowling is represented by hh
5. The total cost is the sum of the cost of shoe rentals for all friends and the cost of booking a lane for the number of hours they go bowling

STEP 2

First, we need to find the total cost of shoe rentals for all friends. This can be done by multiplying the cost of shoe rentals per player by the number of friends.
Costshoes=CostperplayertimesNumberoffriendsCost_{shoes} = Cost_{per\, player} \\times Number\, of\, friends

STEP 3

Now, plug in the given values for the cost per player and the number of friends to form the expression for the cost of shoe rentals.
Costshoes=$5timesfCost_{shoes} = \$5 \\times f

STEP 4

Next, we need to find the total cost of booking a lane for the number of hours they go bowling. This can be done by multiplying the cost of booking a lane per hour by the number of hours.
Costlane=CostperhourtimesNumberofhoursCost_{lane} = Cost_{per\, hour} \\times Number\, of\, hours

STEP 5

Now, plug in the given values for the cost per hour and the number of hours to form the expression for the cost of booking a lane.
Costlane=$45timeshCost_{lane} = \$45 \\times h

STEP 6

Finally, we can find the total cost by adding the cost of shoe rentals and the cost of booking a lane.
Totalcost=Costshoes+CostlaneTotal\, cost = Cost_{shoes} + Cost_{lane}

STEP 7

Substitute the expressions for CostshoesCost_{shoes} and CostlaneCost_{lane} into the equation for TotalcostTotal\, cost.
Totalcost=$5f+$45hTotal\, cost = \$5f + \$45hThe total cost for the group of friends to go bowling is 5f+45h5f +45h dollars.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord