Math

QuestionFind three consecutive even integers that add up to 72.

Studdy Solution

STEP 1

Assumptions1. We are looking for three consecutive even integers. . The sum of these three integers is72.

STEP 2

Let's denote the three consecutive even integers as nn, n+2n+2, and n+4n+4. We choose n+2n+2 and n+4n+4 because even integers always differ by2.

STEP 3

Now, we can write the equation that represents the sum of these three integers.
n+(n+2)+(n+)=72n + (n+2) + (n+) =72

STEP 4

implify the equation by combining like terms.
3n+6=723n +6 =72

STEP 5

Subtract from both sides of the equation to isolate the term with nn.
3n=723n =72 -

STEP 6

Calculate the right side of the equation.
3n=663n =66

STEP 7

Divide both sides of the equation by3 to solve for nn.
n=66/3n =66 /3

STEP 8

Calculate the value of nn.
n=22n =22

STEP 9

Now that we have the value of nn, we can find the other two integers by adding2 and4 to nn respectively.
n+2=22+2n+2 =22 +2n+4=22+4n+4 =22 +4

STEP 10

Calculate the values of n+2n+2 and n+4n+4.
n+2=24n+2 =24n+4=26n+4 =26The three consecutive even integers are22,24, and26.

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