Math

QuestionFind three numbers where their sum is 86, the second is 9 less than the first, and the third is 3 times the first.

Studdy Solution

STEP 1

Assumptions1. The sum of three numbers is86. The second number is9 less than the first number3. The third number is3 times the first number

STEP 2

Let's denote the first number as xx, the second number as yy, and the third number as zz. We can write the given conditions as equations1. x+y+z=86x + y + z =86
2. y=x9y = x -9 . z=xz =x

STEP 3

Now, we can substitute the expressions for yy and zz from the second and third equations into the first equation.
x+(x9)+3x=86x + (x -9) +3x =86

STEP 4

implify the equation by combining like terms.
x9=86x -9 =86

STEP 5

Add9 to both sides of the equation to isolate the term with xx.
5x=86+95x =86 +9

STEP 6

implify the right side of the equation.
5x=955x =95

STEP 7

Divide both sides of the equation by5 to solve for xx.
x=955x = \frac{95}{5}

STEP 8

Calculate the value of xx.
x=955=19x = \frac{95}{5} =19

STEP 9

Now that we have the value of xx, we can find the values of yy and zz by substituting x=19x =19 into the equations y=x9y = x -9 and z=3xz =3x.
For yy, we havey=x9=199y = x -9 =19 -9

STEP 10

Calculate the value of yy.
y=199=10y =19 -9 =10

STEP 11

For zz, we havez=3x=3×19z =3x =3 \times19

STEP 12

Calculate the value of zz.
z=×19=57z = \times19 =57The first number is19, the second number is10, and the third number is57.

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