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Math

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PROBLEM

Find the value of the function f(x)=x3f(x) = x^{3} at x=5x = 5.

STEP 1

Assumptions1. The function f(x) is defined as f(x)=x3f(x) = x^{3}
. The operation \bigsqcup is a mathematical notation often used in set theory to denote the disjoint union of a collection of sets. However, in this context, it seems to be used as a summation symbol. We will assume it to be a summation symbol for the purpose of this problem.
3. The summation is from x=1x=1 to x=5x=5, as no lower limit is provided, we will assume it starts from x=1x=1.

STEP 2

First, we need to find the value of the function f(x)f(x) for each xx from1 to5.
f(x)=xf(x) = x^{}

STEP 3

Now, plug in the values for xx from1 to5 to calculate the value of f(x)f(x) for each xx.
f(1)=13=1f(1) =1^{3} =1f(2)=23=8f(2) =2^{3} =8f(3)=33=27f(3) =3^{3} =27f()=3=64f() =^{3} =64f(5)=53=125f(5) =5^{3} =125

STEP 4

Now that we have the value of f(x)f(x) for each xx from1 to, we can sum these values up to find the value of the given expression.
f(x)=x3x=f(x)=f(1)+f(2)+f(3)+f(4)+f()\bigsqcup_{f(x)=x^{3}}^{x=} f(x) = f(1) + f(2) + f(3) + f(4) + f()

STEP 5

Plug in the values for f(1)f(1), f(2)f(2), f(3)f(3), f(4)f(4), and f(5)f(5) to calculate the sum.
f(x)=x3x=5f(x)=1+8+27+64+125\bigsqcup_{f(x)=x^{3}}^{x=5} f(x) =1 +8 +27 +64 +125

SOLUTION

Calculate the sum.
f(x)=x3x=5f(x)=1+8+27+64+125=225\bigsqcup_{f(x)=x^{3}}^{x=5} f(x) =1 +8 +27 +64 +125 =225The value of the given expression is225.

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