Math  /  Algebra

QuestionThe United States Postal Service charges $0.55\$ 0.55 to mail a first-class letter that weighs up to 1 . ounce. Each additional ounce costs $0.15\$ 0.15. Which equation represents the situation? y=0.15x10.5y=0.15\lfloor x-1\rfloor 0.5 y=0.55x1+0.15y=0.55\lfloor x-1\rfloor+0.15 y=0.55x+0.15y=0.55\lfloor x\rfloor+0.15 y=0.15x+0.55y=0.15\lfloor x\rfloor+0.55

Studdy Solution

STEP 1

What is this asking? We need to find an equation that tells us the cost of mailing a letter based on its weight. Watch out! The first ounce has a different price than the rest, so be careful!

STEP 2

1. Define variables
2. Build the equation
3. Test the equation

STEP 3

Let's use yy to represent the **total cost** in $\$ of mailing the letter.

STEP 4

Let's use xx to represent the **weight** of the letter in ounces.

STEP 5

The **first ounce** costs $0.55\$0.55.
This is our **starting point**.

STEP 6

Each **additional ounce** *after* the first ounce costs $0.15\$0.15.

STEP 7

We can use the greatest integer function (also known as the floor function), written as x\lfloor x \rfloor, which gives us the largest integer *less than or equal to* xx.
For example, 2.3=2\lfloor 2.3 \rfloor = 2 and 1=1\lfloor 1 \rfloor = 1.

STEP 8

For every ounce *after* the first, we add $0.15\$0.15.
So, if a letter weighs xx ounces, we have x1x - 1 additional ounces *after* the first ounce.
The cost of these additional ounces is $0.15x1\$0.15 \cdot \lfloor x - 1 \rfloor if x>1x > 1.
If x1x \leq 1, then x1\lfloor x - 1 \rfloor will be zero or negative, but since we don't get money back for a letter weighing less than one ounce, we can still use this formula.

STEP 9

Putting it all together, the **total cost** yy is the **initial cost** of $0.55\$0.55 plus the **additional cost** of $0.15\$0.15 per ounce after the first ounce: y=0.55+0.15x1 y = 0.55 + 0.15 \cdot \lfloor x - 1 \rfloor

STEP 10

Let's test with a **weight** of x=1x = 1 ounce: y=0.55+0.1511=0.55+0.150=0.55+0.150=0.55 y = 0.55 + 0.15 \cdot \lfloor 1 - 1 \rfloor = 0.55 + 0.15 \cdot \lfloor 0 \rfloor = 0.55 + 0.15 \cdot 0 = 0.55 That's $0.55\$0.55, which is correct!

STEP 11

Now, let's test with x=2.5x = 2.5 ounces: y=0.55+0.152.51=0.55+0.151.5=0.55+0.151=0.55+0.15=0.70 y = 0.55 + 0.15 \cdot \lfloor 2.5 - 1 \rfloor = 0.55 + 0.15 \cdot \lfloor 1.5 \rfloor = 0.55 + 0.15 \cdot 1 = 0.55 + 0.15 = 0.70 That's $0.70\$0.70, which is $0.55\$0.55 for the first ounce and $0.15\$0.15 for the additional ounce, so it works!

STEP 12

The equation that represents the situation is y=0.55+0.15x1 y = 0.55 + 0.15 \cdot \lfloor x - 1 \rfloor , which is equivalent to the provided option y=0.15x1+0.5y=0.15\lfloor x-1\rfloor + 0.5.

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