Math

Question Find the value of yy when x=28x=28, given that yy varies directly with xx and y=20y=20 when x=16x=16.

Studdy Solution

STEP 1

Assumptions
1. The value of "y" varies directly with "x". This means there is a constant "k" such that y=kxy=kx.
2. When y=20y=20, x=16x=16.
3. We need to find the value of yy when x=28x=28.

STEP 2

First, we need to find the constant of variation "k". We can do this by rearranging the equation y=kxy=kx to solve for "k".
k=yxk = \frac{y}{x}

STEP 3

Now, plug in the given values for yy and xx to calculate "k".
k=2016k = \frac{20}{16}

STEP 4

Calculate the value of "k".
k=2016=1.25k = \frac{20}{16} = 1.25

STEP 5

Now that we have the value of "k", we can use this to find the value of yy when x=28x=28. Substitute the values of "k" and "x" into the equation y=kxy=kx.
y=1.25×28y = 1.25 \times 28

STEP 6

Calculate the value of yy.
y=1.25×28=35y = 1.25 \times 28 = 35
The value of yy when x=28x=28 is 35.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord