Math

QuestionFind the perimeter of a rectangle with width (5v2w)(5 v-2 w) cm and length (6v+7w)(6 v+7 w) cm.

Studdy Solution

STEP 1

Assumptions1. The width of the rectangle is given by the expression (5vw)(5v -w) centimeters. The length of the rectangle is given by the expression (6v+7w)(6v +7w) centimeters3. The perimeter of a rectangle is given by the formula (length+width)*(length + width)

STEP 2

We need to find the perimeter of the rectangle. We can do this by substituting the given expressions for the length and width into the formula for the perimeter of a rectangle.
Perimeter=2(Length+Width)Perimeter =2*(Length + Width)

STEP 3

Now, plug in the given expressions for the length and width into the formula.
Perimeter=2((6v+7w)+(5v2w))Perimeter =2*((6v +7w) + (5v -2w))

STEP 4

implify the expression inside the parentheses.
Perimeter=2(11v+w)Perimeter =2*(11v +w)

STEP 5

istribute the2 across the terms inside the parentheses to calculate the perimeter.
Perimeter=211v+25wPerimeter =2*11v +2*5w

STEP 6

implify the expression to get the final answer.
Perimeter=22v+10wPerimeter =22v +10wSo, the expression that represents the perimeter, in centimeters, of the rectangle is 22v+10w22v +10w.

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