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QuestionCalculate the wind chill WW for t=5∘Ct=5^{\circ} \mathrm{C} and v=39 m/sv=39 \mathrm{~m/s}. Round to the nearest degree.

Studdy Solution

STEP 1

Assumptions1. The wind speed is39 m/s. The air temperature is5°C3. The wind chill factor is given by the provided formula4. The wind speed is greater than20 m/s, so we use the third condition of the formula

STEP 2

We will use the third condition of the formula to calculate the wind chill factor, as the wind speed is greater than20 m/s.
W=33−1.5958(33−t)W =33 -1.5958(33 - t)

STEP 3

Now, plug in the given value for the air temperature into the formula.
W=33−1.5958(33−5)W =33 -1.5958(33 -5)

STEP 4

First, calculate the value inside the parentheses.
W=33−1.5958×28W =33 -1.5958 \times28

STEP 5

Now, calculate the multiplication.
W=33−44.6824W =33 -44.6824

STEP 6

Finally, subtract the second term from33 to find the wind chill.
W=33−44.6824=−11.6824W =33 -44.6824 = -11.6824

STEP 7

The wind chill factor is a negative number, which means it's below freezing. However, the problem asks us to round to the nearest degree. So, we round -11.6824 to -12.
W≈−12∘CW \approx -12^{\circ}CThe wind chill for an air temperature of 5∘C5^{\circ}C and a wind speed of 39m/s39 m/s is approximately −12∘C-12^{\circ}C.

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