Math  /  Algebra

QuestionTHIS IS A PRACTICE TEST 22 \square Mark for Review (45)
A line in the xyx y-plane has a slope of 19\frac{1}{9} and passes through the point (0,14)(0,14). Which equation represents this line? (A) y=19x14y=-\frac{1}{9} x-14 (B) y=19x+14y=-\frac{1}{9} x+14 (C) y=19x14y=\frac{1}{9} x-14
D y=19x+14y=\frac{1}{9} x+14

Studdy Solution

STEP 1

1. The line has a slope of 19\frac{1}{9}.
2. The line passes through the point (0,14)(0, 14).
3. We are looking for the equation of the line in the form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.

STEP 2

1. Identify the slope and y-intercept.
2. Write the equation of the line using the slope-intercept form.
3. Match the equation to the given options.

STEP 3

Identify the slope and y-intercept.
The slope mm is given as 19\frac{1}{9}.
The line passes through the point (0,14)(0, 14), which means the y-intercept bb is 1414.

STEP 4

Write the equation of the line using the slope-intercept form y=mx+by = mx + b.
Substitute the values of mm and bb into the equation:
y=19x+14 y = \frac{1}{9}x + 14

STEP 5

Match the equation to the given options.
The equation y=19x+14y = \frac{1}{9}x + 14 matches option (D).
The correct equation representing the line is:
y=19x+14 \boxed{y = \frac{1}{9}x + 14}

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