Math

QuestionSolve the equation: 3x+237+x+365=13\frac{3 x+23}{7}+\frac{x+36}{5}=13. Provide an integer or simplified fraction as the solution.

Studdy Solution

STEP 1

Assumptions1. The equation is 3x+237+x+365=13\frac{3 x+23}{7}+\frac{x+36}{5}=13 . The solution set is a set of real numbers

STEP 2

To simplify the equation, we first need to find a common denominator for the fractions. The least common multiple of7 and5 is35.

STEP 3

Multiply each term by35 to get rid of the denominators.
353x+237+35x+365=351335 \cdot \frac{3 x+23}{7}+35 \cdot \frac{x+36}{5}=35 \cdot13

STEP 4

implify each term.
(3x+23)+7(x+36)=3513(3x+23) +7(x+36) =35 \cdot13

STEP 5

istribute the5 and7 in each term.
15x+115+7x+252=45515x +115 +7x +252 =455

STEP 6

Combine like terms.
22x+367=45522x +367 =455

STEP 7

Subtract367 from both sides to isolate the variable term.
22x=45536722x =455 -367

STEP 8

Calculate the right side.
22x=8822x =88

STEP 9

Divide both sides by22 to solve for x.
x=8822x = \frac{88}{22}

STEP 10

Calculate the value of x.
x=4x =4The solution set is {4}.

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