Math  /  Geometry

QuestionTo find the height hh of Mount St. Melon in the Cantaloupe Mountains, two angle measurements were taken 1200 feet apart along a direct line toward the mountain. Using these measurements, find the height of the mountain. Homework Help

Studdy Solution

STEP 1

What is this asking? We need to figure out how tall Mount St.
Melon is using two angles measured from different spots a known distance apart. Watch out! Don't mix up the angles and distances!
Make sure you're using the right measurements for the right parts of the triangles.

STEP 2

1. Set up the problem
2. Find the distance to the mountain
3. Calculate the height

STEP 3

Alright, imagine we're looking at this mountain from two different spots.
We've got two angles, 3535^\circ and 4242^\circ, and we know the distance between those spots is **1200 feet**.
Let's call the distance from the closer spot to the base of the mountain xx.

STEP 4

We can actually think of this as two right triangles!
One big one with the 3535^\circ angle, and a smaller one inside it with the 4242^\circ angle.
Both triangles share the same height, which is what we want to find.

STEP 5

Let's use some trigonometry!
For the bigger triangle with the 3535^\circ angle, we know that tan(35)=hx+1200\tan(35^\circ) = \frac{h}{x + 1200}.
Remember, tangent is opposite over adjacent.

STEP 6

For the smaller triangle with the 4242^\circ angle, we have tan(42)=hx\tan(42^\circ) = \frac{h}{x}.
Same idea, tangent is opposite over adjacent.

STEP 7

Now we have two equations with two unknowns, hh and xx.
Let's solve for xx first.
From the second equation, we get h=xtan(42)h = x \cdot \tan(42^\circ).
Let's substitute this into the first equation: tan(35)=xtan(42)x+1200\tan(35^\circ) = \frac{x \cdot \tan(42^\circ)}{x + 1200}.

STEP 8

Time to rearrange!
Multiply both sides by x+1200x + 1200 to get tan(35)(x+1200)=xtan(42)\tan(35^\circ)(x + 1200) = x \cdot \tan(42^\circ).
Distribute the tan(35)\tan(35^\circ) to get xtan(35)+1200tan(35)=xtan(42)x \cdot \tan(35^\circ) + 1200 \cdot \tan(35^\circ) = x \cdot \tan(42^\circ).

STEP 9

Now, move the xx terms to one side: 1200tan(35)=xtan(42)xtan(35)1200 \cdot \tan(35^\circ) = x \cdot \tan(42^\circ) - x \cdot \tan(35^\circ).
Factor out the xx to get 1200tan(35)=x(tan(42)tan(35))1200 \cdot \tan(35^\circ) = x(\tan(42^\circ) - \tan(35^\circ)).

STEP 10

Finally, divide both sides by (tan(42)tan(35))(\tan(42^\circ) - \tan(35^\circ)) to isolate xx: x=1200tan(35)tan(42)tan(35)x = \frac{1200 \cdot \tan(35^\circ)}{\tan(42^\circ) - \tan(35^\circ)}.
Plugging in the values for the tangents, we get x=12000.70020.90040.7002=840.240.20024196.9x = \frac{1200 \cdot 0.7002}{0.9004 - 0.7002} = \frac{840.24}{0.2002} \approx 4196.9.
So, x4196.9 feetx \approx \textbf{4196.9 feet}.

STEP 11

Now that we know xx, we can plug it back into either of our original equations to find hh.
Let's use the simpler one: h=xtan(42)h = x \cdot \tan(42^\circ).

STEP 12

Substituting our value for xx, we get h=4196.9tan(42)=4196.90.90043778.9h = 4196.9 \cdot \tan(42^\circ) = 4196.9 \cdot 0.9004 \approx 3778.9.

STEP 13

The height of Mount St.
Melon is approximately **3778.9 feet**!

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