Math

QuestionTranspose the following equations to make the letter in brackets the subject: 1) k=s+ntk=s+n t (s) 2) x=abcx=a b c (c) 3) x=stx=s t (s) 4) c=qt+pc=q t+p (p) 5) y=mx+cy=m x+c (m) 6) A=hw+2A=hw+2 (w) 7) AB=CDAB=CD (D) 8) dk3=c\frac{dk}{3}=c (k)

Studdy Solution

STEP 1

Assumptions1. All the variables in the equations are real numbers. . The equations are linear equations.
3. Transposing means isolating the variable in brackets on one side of the equation.

STEP 2

For the first equation, we need to make 's' the subject. We can do this by subtracting 'nt' from both sides of the equation.
s=knts = k - nt

STEP 3

For the second equation, we need to make 'c' the subject. We can do this by dividing both sides of the equation by 'ab'.
c=xabc = \frac{x}{ab}

STEP 4

For the third equation, we need to make 's' the subject. We can do this by dividing both sides of the equation by 't'.
s=xts = \frac{x}{t}

STEP 5

For the fourth equation, we need to make 'p' the subject. We can do this by subtracting 'qt' from both sides of the equation.
p=cqtp = c - qt

STEP 6

For the fifth equation, we need to make 'm' the subject. We can do this by subtracting 'c' from both sides of the equation and then dividing by 'x'.
m=ycxm = \frac{y - c}{x}

STEP 7

For the sixth equation, we need to make 'w' the subject. We can do this by subtracting '2' from both sides of the equation and then dividing by 'h'.
w=A2hw = \frac{A -2}{h}

STEP 8

For the seventh equation, we need to make '' the subject. We can do this by dividing both sides of the equation by 'C'.
=ABC = \frac{AB}{C}

STEP 9

For the eighth equation, we need to make 'k' the subject. We can do this by multiplying both sides of the equation by '3'.
k=3ck =3c

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