Math

QuestionTrova il vettore normale ai seguenti piani: 1) xy+5=0x - y + 5 = 0, 2) 2yz+1=02y - z + 1 = 0, 3) x+2yz=0x + 2y - z = 0, 4) 12xy+7z+4=012x - y + 7z + 4 = 0.

Studdy Solution

STEP 1

Question: What is the standard form of the equation of a plane?
A) Ax + By + Cz = D B) Ax + By + C = D C) A + Bx + Cy = D D) Ax + By = Cz + D
Answer: A) Ax + By + Cz = D

STEP 2

Question: Given the equation of the plane x-y+5=0, what are the coefficients of x, y, and z?
A) 1, -1, 0 B) 1, -1, 5 C) x, y, 5 D) 1, -y, 0
Answer: A) 1, -1, 0

STEP 3

Question: What is the normal vector to the plane x-y+5=0?
A) (1, -1, 0) B) (1, -1, 5) C) (x, y, z) D) (1, -y, 0)
Answer: A) (1, -1, 0)

STEP 4

Question: For the equation of the plane 2y-z+1=0, after rewriting it in the standard form, what are the coefficients of x, y, and z?
A) 0, 2, -1 B) 2, -1, 0 C) 1, 2, -1 D) 0, -1, 2
Answer: A) 0, 2, -1

STEP 5

Question: What is the normal vector to the plane 12x-y+7z+4=0?
A) (12, -1, 7) B) (-1, 12, 7) C) (12, 7, -1) D) (4, -1, 7)
Answer: A) (12, -1, 7)

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