QuestionTwo buses start 516 miles apart and meet in 4 hours. One is slower. Find their speeds.
Studdy Solution
STEP 1
Assumptions1. The two buses start516 miles apart.
. They travel towards each other.
3. One bus travels15 mi/h slower than the other.
4. They meet after4 hours.
STEP 2
Let's denote the speed of the faster bus as (mi/h). Therefore, the speed of the slower bus is (mi/h).
STEP 3
We know that the total distance covered by both buses is516 miles. Since they are traveling towards each other, the total distance covered is the sum of the distances covered by each bus.
STEP 4
We also know that distance is the product of speed and time. So, we can express the distances covered by each bus in terms of their speeds and the time they traveled.
STEP 5
Now, we can plug in the given values for the total distance and the time to get an equation in terms of .
STEP 6
implify the equation by distributing the4 on the right side.
STEP 7
Combine like terms on the right side of the equation.
STEP 8
Add60 to both sides of the equation to isolate the term with on one side.
STEP 9
implify the left side of the equation.
STEP 10
Divide both sides of the equation by8 to solve for .
STEP 11
Calculate the value of .
So, the speed of the faster bus is72 mi/h.
STEP 12
Now, we can find the speed of the slower bus by subtracting15 from the speed of the faster bus.
STEP 13
Plug in the value for to calculate the speed of the slower bus.
STEP 14
Calculate the speed of the slower bus.
So, the speed of the slower bus is57 mi/h.
The rates of the buses are72 mi/h and57 mi/h.
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