Math Snap

STEP 1

Assumptions1. The weight of the first metal is $3.116 \mathrm{~g} \pm0.000 \mathrm{~g}$
. The weight of the second metal is $4.6617 \mathrm{~g} \pm0.000 \mathrm{~g}$
3. The weight of the beaker is $35.4478 \mathrm{~g} \pm0.000 \mathrm{~g}$
4. The total mass is the sum of the masses of the two metals and the beaker5. The total error is the sum of the absolute errors of the two metals and the beaker

STEP 2

First, we need to calculate the total mass of the beaker and the metals. We can do this by adding the masses of the two metals and the beaker.
$$Total\, mass = Mass\, of\, first\, metal + Mass\, of\, second\, metal + Mass\, of\, beaker$$

STEP 3

Now, plug in the given values for the masses of the first metal, second metal, and beaker to calculate the total mass.
$$Total\, mass =3.1162 \mathrm{~g} +.6617 \mathrm{~g} +35.4478 \mathrm{~g}$$

STEP 4

Calculate the total mass.
$$Total\, mass =3.1162 \mathrm{~g} +4.6617 \mathrm{~g} +35.4478 \mathrm{~g} =43.2257 \mathrm{~g}$$

STEP 5

Next, we need to calculate the total error. We can do this by adding the absolute errors of the two metals and the beaker.
$$Total\, error = Error\, of\, first\, metal + Error\, of\, second\, metal + Error\, of\, beaker$$

STEP 6

Now, plug in the given values for the errors of the first metal, second metal, and beaker to calculate the total error.
$$Total\, error =0.0002 \mathrm{~g} +0.0002 \mathrm{~g} +0.0002 \mathrm{~g}$$

Calculate the total error.
$$Total\, error =0.0002 \mathrm{~g} +0.0002 \mathrm{~g} +0.0002 \mathrm{~g} =0.0006 \mathrm{~g}$$The total mass of the beaker and the metals combined is $43.2257 \mathrm{~g} \pm0.0006 \mathrm{~g}$.