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QuestionSolve the equation 2(4w−1)=−10(w−3)+42(4w - 1) = -10(w - 3) + 4.

Studdy Solution

STEP 1

Assumptions1. The equation is (4w−1)=−10(w−3)+4(4 w-1)=-10(w-3)+4 . We are solving for the variable ww

STEP 2

First, we need to distribute the numbers outside the parentheses on both sides of the equation.
2(4w−1)=−10(w−)+42(4 w-1)=-10(w-)+4becomes8w−2=−10w+30+48w -2 = -10w +30 +4

STEP 3

Next, we simplify the right side of the equation by adding the constants together.
8w−2=−10w+348w -2 = -10w +34

STEP 4

Now, we need to isolate the variable ww on one side of the equation. We can do this by adding 10w10w to both sides of the equation.
8w+10w=−10w+10w+348w +10w = -10w +10w +34which simplifies to18w=34+218w =34 +2

STEP 5

Next, we simplify the right side of the equation by adding the constants together.
18w=3618w =36

STEP 6

Finally, we solve for ww by dividing both sides of the equation by18.
w=3618w = \frac{36}{18}

STEP 7

implify the right side of the equation to find the value of ww.
w=2w =2So, the solution to the equation 2(4w−1)=−10(w−3)+42(4 w-1)=-10(w-3)+4 is w=2w =2.

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