Math

QuestionSolve for bb in the equation 2(6b+8)=6b+42(6 b+8)=6 b+4.

Studdy Solution

STEP 1

Assumptions1. We are given the equation (6b+8)=6b+4(6b+8)=6b+4 . We are asked to solve for bb

STEP 2

First, we need to distribute the 22 on the left side of the equation.
2(6b+8)=2times6b+2times82(6b+8) =2 \\times6b +2 \\times8

STEP 3

Now, plug in the values to calculate the left side of the equation.
2times6b+2times8=12b+162 \\times6b +2 \\times8 =12b +16

STEP 4

Now, we replace the left side of the original equation with the result from the previous step.
12b+16=6b+412b +16 =6b +4

STEP 5

Next, we need to isolate bb by getting all terms with bb on one side of the equation and the constants on the other side. We can do this by subtracting bb from both sides.
12bb=bb+412b -b =b -b +4

STEP 6

Now, simplify both sides of the equation.
6b=46b =4

STEP 7

Finally, to solve for bb, we divide both sides of the equation by 66.
b=46b = \frac{4}{6}

STEP 8

implify the fraction to get the final solution.
b=23b = \frac{2}{3}So, the solution to the equation 2(6b+8)=6b+42(6b+8)=6b+4 is b=23b = \frac{2}{3}.

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