Math

QuestionSolve for the unknowns in the equation: 2x4y?z33x?y3z?=2x23yz7\frac{2 x^{4} y^{?} z^{-3}}{3 x^{?} y^{-3} z^{?}}=\frac{2 x^{2}}{3 y z^{7}}.

Studdy Solution

STEP 1

Assumptions1. We assume that the bases on both sides of the equation are equal. . We assume that the powers of the same base on both sides of the equation are equal.

STEP 2

First, we equate the powers of xx on both sides of the equation.4?=24 - ? =2

STEP 3

olving the equation for the unknown, we get?=2? = -2

STEP 4

Calculate the value of the unknown.
?=42=2? =4 -2 =2So, the power of xx in the denominator is2.

STEP 5

Next, we equate the powers of yy on both sides of the equation.
?(3)=1? - (-3) = -1

STEP 6

olving the equation for the unknown, we get?=13? = -1 -3

STEP 7

Calculate the value of the unknown.
?=13=4? = -1 -3 = -4So, the power of yy in the numerator is -4.

STEP 8

Finally, we equate the powers of zz on both sides of the equation.
3?=7-3 - ? =7

STEP 9

olving the equation for the unknown, we get?=37? = -3 -7

STEP 10

Calculate the value of the unknown.
?=37=10? = -3 -7 = -10So, the power of zz in the denominator is -10.
The solution is the power of xx in the denominator is2, the power of yy in the numerator is -4, and the power of zz in the denominator is -10.

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