Math  /  Trigonometry

QuestionUse a sum-to-product formula to find the exact value. Write your answer as a simplified fraction and rationalize the denominator, if nece sin165sin75=\sin 165^{\circ}-\sin 75^{\circ}= \square  延 \sqrt{\text { 延 }}

Studdy Solution

STEP 1

1. We are asked to find the exact value of the expression using a sum-to-product formula.
2. The sum-to-product identities can be used to simplify expressions involving sine and cosine.
3. The expression involves angles in degrees.

STEP 2

1. Identify and apply the appropriate sum-to-product formula.
2. Simplify the resulting expression.
3. Rationalize the denominator if necessary.

STEP 3

Identify the sum-to-product formula for sine differences:
The formula is: sinAsinB=2cos(A+B2)sin(AB2) \sin A - \sin B = 2 \cos \left( \frac{A + B}{2} \right) \sin \left( \frac{A - B}{2} \right)
Apply this formula to the given expression sin165sin75\sin 165^{\circ} - \sin 75^{\circ}.
A=165,B=75 A = 165^{\circ}, \quad B = 75^{\circ}
sin165sin75=2cos(165+752)sin(165752) \sin 165^{\circ} - \sin 75^{\circ} = 2 \cos \left( \frac{165^{\circ} + 75^{\circ}}{2} \right) \sin \left( \frac{165^{\circ} - 75^{\circ}}{2} \right)

STEP 4

Calculate the angles inside the cosine and sine functions:
165+752=2402=120 \frac{165^{\circ} + 75^{\circ}}{2} = \frac{240^{\circ}}{2} = 120^{\circ}
165752=902=45 \frac{165^{\circ} - 75^{\circ}}{2} = \frac{90^{\circ}}{2} = 45^{\circ}
Substitute these values back into the expression:
2cos(120)sin(45) 2 \cos(120^{\circ}) \sin(45^{\circ})

STEP 5

Use known values for trigonometric functions:
cos(120)=12 \cos(120^{\circ}) = -\frac{1}{2} sin(45)=22 \sin(45^{\circ}) = \frac{\sqrt{2}}{2}
Substitute these into the expression:
2(12)(22) 2 \left(-\frac{1}{2}\right) \left(\frac{\sqrt{2}}{2}\right)
Simplify the expression:
=2222=22 = -\frac{2}{2} \cdot \frac{\sqrt{2}}{2} = -\frac{\sqrt{2}}{2}

STEP 6

The expression is already simplified as a fraction and the denominator is rationalized.
The exact value is:
22 \boxed{-\frac{\sqrt{2}}{2}}

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