PROBLEM
Use f(x)=x2−9 and g(x)=x2+9 to find a formula for each expression. Identify its domain.
(a) (f+g)(x)
(c) (fg)(x)
(b) (f−g)(x)
(d) (f/g)(x)
(a) (f+g)(x)= □ (Simplify your answer. Do not factor.)
STEP 1
1. We are given two functions, f(x)=x2−9 and g(x)=x2+9.
2. We need to find formulas for the expressions (f+g)(x), (f−g)(x), (fg)(x), and (f/g)(x).
3. We need to identify the domain for each expression.
4. The domain of a function is the set of all possible input values (x-values) for which the function is defined.
STEP 2
1. Calculate (f+g)(x) and identify its domain.
2. Calculate (f−g)(x) and identify its domain.
3. Calculate (fg)(x) and identify its domain.
4. Calculate (f/g)(x) and identify its domain.
STEP 3
Calculate (f+g)(x) by adding the functions f(x) and g(x):
(f+g)(x)=f(x)+g(x)=(x2−9)+(x2+9) Combine like terms:
(f+g)(x)=x2−9+x2+9=2x2 The domain of (f+g)(x) is all real numbers, since there are no restrictions on x for a polynomial.
STEP 4
Calculate (f−g)(x) by subtracting the functions f(x) and g(x):
(f−g)(x)=f(x)−g(x)=(x2−9)−(x2+9) Combine like terms:
(f−g)(x)=x2−9−x2−9=−18 The domain of (f−g)(x) is all real numbers, since it is a constant function.
STEP 5
Calculate (fg)(x) by multiplying the functions f(x) and g(x):
(fg)(x)=f(x)⋅g(x)=(x2−9)(x2+9) Use the difference of squares formula:
(fg)(x)=(x2)2−(9)2=x4−81 The domain of (fg)(x) is all real numbers, since it is a polynomial.
SOLUTION
Calculate (f/g)(x) by dividing the functions f(x) and g(x):
(f/g)(x)=g(x)f(x)=x2+9x2−9 The domain of (f/g)(x) is all real numbers except where the denominator is zero. Since x2+9 is never zero for real x, the domain is all real numbers.
The formulas and domains are as follows:
(a) (f+g)(x)=2x2, Domain: all real numbers.
(b) (f−g)(x)=−18, Domain: all real numbers.
(c) (fg)(x)=x4−81, Domain: all real numbers.
(d) (f/g)(x)=x2+9x2−9, Domain: all real numbers.
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