Math

Question Use synthetic division to find f(2),f(5),f(6)f(2), f(-5), f(6) for f(x)=x313x2+52x60f(x)=x^{3}-13 x^{2}+52 x-60. Simplify your answers.

Studdy Solution

STEP 1

Assumptions
1. The given function is f(x)=x313x2+52x60f(x) = x^3 - 13x^2 + 52x - 60.
2. We need to find the values of f(2)f(2), f(5)f(-5), and f(6)f(6) using synthetic division.
3. After finding the values, we will check the results using a graphing calculator.

STEP 2

To find f(2)f(2), we set up synthetic division with 2 as the root we are testing.
2113526022260 \begin{array}{r|rrrr} 2 & 1 & -13 & 52 & -60 \\ \hline & & 2 & -22 & 60 \\ \end{array}

STEP 3

Perform the synthetic division operations.
2113526021=22(11)=22230=60 \begin{array}{r|rrrr} 2 & 1 & -13 & 52 & -60 \\ \hline & & 2\cdot1=2 & 2\cdot(-11)=-22 & 2\cdot30=60 \\ \end{array}
2113+2522260+6011300 \begin{array}{r|rrrr} 2 & 1 & -13+2 & 52-22 & -60+60 \\ \hline & & -11 & 30 & 0 \\ \end{array}

STEP 4

Read off the remainder from the bottom row of the synthetic division. This is the value of f(2)f(2).
f(2)=0f(2) = 0

STEP 5

To find f(5)f(-5), we set up synthetic division with -5 as the root we are testing.
51135260590460 \begin{array}{r|rrrr} -5 & 1 & -13 & 52 & -60 \\ \hline & & -5 & 90 & -460 \\ \end{array}

STEP 6

Perform the synthetic division operations.
5113526051=55(18)=905142=710 \begin{array}{r|rrrr} -5 & 1 & -13 & 52 & -60 \\ \hline & & -5\cdot1=-5 & -5\cdot(-18)=90 & -5\cdot142=-710 \\ \end{array}
5113552+906071018142770 \begin{array}{r|rrrr} -5 & 1 & -13-5 & 52+90 & -60-710 \\ \hline & & -18 & 142 & -770 \\ \end{array}

STEP 7

Read off the remainder from the bottom row of the synthetic division. This is the value of f(5)f(-5).
f(5)=770f(-5) = -770

STEP 8

To find f(6)f(6), we set up synthetic division with 6 as the root we are testing.
6113526064260 \begin{array}{r|rrrr} 6 & 1 & -13 & 52 & -60 \\ \hline & & 6 & -42 & 60 \\ \end{array}

STEP 9

Perform the synthetic division operations.
6113526061=66(7)=42610=60 \begin{array}{r|rrrr} 6 & 1 & -13 & 52 & -60 \\ \hline & & 6\cdot1=6 & 6\cdot(-7)=-42 & 6\cdot10=60 \\ \end{array}
6113+6524260+607100 \begin{array}{r|rrrr} 6 & 1 & -13+6 & 52-42 & -60+60 \\ \hline & & -7 & 10 & 0 \\ \end{array}

STEP 10

Read off the remainder from the bottom row of the synthetic division. This is the value of f(6)f(6).
f(6)=0f(6) = 0

STEP 11

To check our work, we use a graphing calculator to plot the function f(x)=x313x2+52x60f(x) = x^3 - 13x^2 + 52x - 60 and evaluate f(2)f(2), f(5)f(-5), and f(6)f(6).

STEP 12

After plotting the function on a graphing calculator, we find the points on the graph corresponding to x=2x = 2, x=5x = -5, and x=6x = 6 to verify the values obtained through synthetic division.

STEP 13

The graphing calculator should confirm that f(2)=0f(2) = 0, f(5)=770f(-5) = -770, and f(6)=0f(6) = 0.
The function values are: f(2)=0f(2) = 0 f(5)=770f(-5) = -770 f(6)=0f(6) = 0

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