Math

QuestionEvaluate the function f(x)=x4x28f(x)=\frac{\sqrt{x-4}}{x^{2}-8} for f(7)f(7), f(6)f(-6), and f(4.3)f(4.3).

Studdy Solution

STEP 1

Assumptions1. The function is defined as f(x)=x4x8f(x)=\frac{\sqrt{x-4}}{x^{}-8} . We need to evaluate f(7)f(7), f(6)f(-6), and f(4.3)f(4.3)3. We will use the given function to find the values

STEP 2

First, let's evaluate f(7)f(7). Substitute x=7x=7 into the function.
f(7)=74728f(7)=\frac{\sqrt{7-4}}{7^{2}-8}

STEP 3

implify the expression inside the square root and the denominator.
f(7)=3498f(7)=\frac{\sqrt{3}}{49-8}

STEP 4

Further simplify the denominator.
f(7)=341f(7)=\frac{\sqrt{3}}{41}So, f(7)=341f(7)=\frac{\sqrt{3}}{41} is the correct answer for part (a).

STEP 5

Next, let's evaluate f()f(-). Substitute x=x=- into the function.
f()=4()28f(-)=\frac{\sqrt{--4}}{(-)^{2}-8}

STEP 6

implify the expression inside the square root and the denominator.
f(6)=10368f(-6)=\frac{\sqrt{-10}}{36-8}

STEP 7

Since the square root of a negative number is undefined in the real number system, we can conclude that f(6)f(-6) is undefined.
So, f(6)f(-6) is undefined is the correct answer for part (b).

STEP 8

Finally, let's evaluate f(4.3)f(4.3). Substitute x=4.3x=4.3 into the function.
f(4.3)=4.34(4.3)28f(4.3)=\frac{\sqrt{4.3-4}}{(4.3)^{2}-8}

STEP 9

implify the expression inside the square root and the denominator.
f(4.3)=.318.498f(4.3)=\frac{\sqrt{.3}}{18.49-8}

STEP 10

Further simplify the denominator.
f(4.3)=0.310.49f(4.3)=\frac{\sqrt{0.3}}{10.49}So, f(4.3)=0.310.49f(4.3)=\frac{\sqrt{0.3}}{10.49} is the correct answer for part (c).

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