Math  /  Algebra

QuestionUse the table to determine if ff is one-to-one. \begin{tabular}{|r|l|l|l|l|} \hlinexx & -3 & -6 & -5 & -2 \\ \hlinef(x)f(x) & -2 & -4 & -2 & -1 \\ \hline \end{tabular}
Is f one-to-one? No Yes

Studdy Solution

STEP 1

What is this asking? Does every input (xx) in our table have a unique output (f(x)f(x))? Watch out! Don't get tricked!
Just because different inputs *can* have the same output doesn't mean they *always* do.
We need to check *all* the inputs and outputs in the table.

STEP 2

1. Check for duplicate outputs.
2. Determine if the function is one-to-one.

STEP 3

Let's **scan** the f(x)f(x) row in our table.
We're looking for any repeats, any outputs that show up more than once.
Do you see any?
I see a **-2** appearing twice!

STEP 4

Specifically, f(3)=2f(-3) = -2 and f(5)=2f(-5) = -2.
This means two different inputs, 3-3 and 5-5, give us the same output, 2-2.

STEP 5

A function is **one-to-one** if every input has *exactly* one output, and every output has *exactly* one input.
It's like a perfect matching game!

STEP 6

Since we found two inputs, 3-3 and 5-5, that both produce the same output, 2-2, this function breaks the one-to-one rule.
It's like having two left shoes for the same right foot!

STEP 7

No, ff is *not* one-to-one.

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