Math

QuestionEstimate the average rate of change of V(t)V(t) from t=2t=2 to t=6t=6 using points (2,500)(2,500) and (6,1200)(6,1200). Interpret the result.

Studdy Solution

STEP 1

Assumptions1. The values of V(t)V(t) at different points of time tt are as follows (0,400)(0,400), (,500)(,500), (4,900)(4,900), (6,1200)(6,1200), (8,1250)(8,1250). . We are asked to estimate the average rate of change of V(t)V(t) with respect to tt over the interval [,6][,6].

STEP 2

The average rate of change of a function over an interval [a,b][a,b] is given by the difference in the function values at the end points of the interval divided by the difference in the end points of the interval.
Averagerateofchange=V(b)V(a)baAverage\, rate\, of\, change = \frac{V(b) - V(a)}{b - a}

STEP 3

Now, plug in the given values for aa, bb, V(a)V(a), and V(b)V(b) to calculate the average rate of change.
Averagerateofchange=V(6)V(2)62Average\, rate\, of\, change = \frac{V(6) - V(2)}{6 -2}

STEP 4

From the given points, we know that V(2)=500V(2) =500 and V(6)=1200V(6) =1200.
Averagerateofchange=120050062Average\, rate\, of\, change = \frac{1200 -500}{6 -2}

STEP 5

Calculate the average rate of change.
Averagerateofchange=7004Average\, rate\, of\, change = \frac{700}{4}

STEP 6

The average rate of change is175.
The average rate of change of V(t)V(t) with respect to tt over the interval [2,6][2,6] is175. This means that, on average, the value of subprime mortgage debt outstanding in the United States increased by 175billionperyearoverthe4yearperiodfrom175 billion per year over the4-year period from t=2to to t=6$.

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