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PROBLEM

Using the substitution: u=x92u=x^{9}-2. Re-write the indefinite integral then evaluate in terms of uu.
10x8(x92)10dx=u10109du=1099u11+c\int 10 x^{8}\left(x^{9}-2\right)^{10} d x=\int u^{10} \frac{10}{9} d u=\frac{10}{99} u^{11}+c

STEP 1

1. We are given an integral with a substitution provided.
2. The substitution is u=x92 u = x^9 - 2 .
3. We need to rewrite the integral in terms of u u and evaluate it.

STEP 2

1. Identify and perform the substitution.
2. Rewrite the integral in terms of u u .
3. Evaluate the integral in terms of u u .
4. Substitute back to express the result in terms of x x .

STEP 3

Identify the substitution: u=x92 u = x^9 - 2 .
Calculate the derivative of u u with respect to x x :
dudx=9x8 \frac{du}{dx} = 9x^8 This implies:
du=9x8dx du = 9x^8 \, dx Solve for dx dx :
dx=19x8du dx = \frac{1}{9x^8} \, du

STEP 4

Substitute u=x92 u = x^9 - 2 and dx=19x8du dx = \frac{1}{9x^8} \, du into the integral:
10x8(x92)10dx=10x8u1019x8du \int 10 x^8 (x^9 - 2)^{10} \, dx = \int 10 x^8 u^{10} \cdot \frac{1}{9x^8} \, du Simplify the expression:
=109u10du = \int \frac{10}{9} u^{10} \, du

STEP 5

Evaluate the integral in terms of u u :
109u10du=109111u11+c \int \frac{10}{9} u^{10} \, du = \frac{10}{9} \cdot \frac{1}{11} u^{11} + c =1099u11+c = \frac{10}{99} u^{11} + c

SOLUTION

Substitute back u=x92 u = x^9 - 2 to express the result in terms of x x :
1099(x92)11+c \frac{10}{99} (x^9 - 2)^{11} + c

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