Math  /  Data & Statistics

QuestionVideo: How to Find T-Value from a T-Table? t-table.pdf \square What is the tt value with a 95%95 \% confidence interval for the true population mean if the sample size n=23\mathrm{n}=23 ? (Please keep three decimal places) t value = \square Submit Question

Studdy Solution

STEP 1

1. The sample size n=23 n = 23 .
2. The degrees of freedom df=n1 df = n - 1 .
3. We are looking for a two-tailed t t -value corresponding to a 95% 95\% confidence interval.

STEP 2

1. Calculate the degrees of freedom.
2. Locate the t t -value in the t t -table using the degrees of freedom and the confidence level.

STEP 3

Calculate the degrees of freedom:
df=n1=231=22 df = n - 1 = 23 - 1 = 22

STEP 4

Use the t t -table to find the t t -value for df=22 df = 22 and a 95% 95\% confidence interval. This corresponds to a two-tailed test with α=0.05 \alpha = 0.05 .
The t t -value is approximately:
2.074 \boxed{2.074}

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