QuestionFind the constant $x$ in the equation $H=x \frac{v}{A}$ from $v=\frac{7}{4} A H$ .

Studdy Solution

STEP 1

Assumptions1. The volume of the figure is given by the equation $v=\frac{7}{4} A H$ . The equation can be rewritten in the form $H=x \frac{v}{A}$ , where $x$ is a constant3. We need to find the value of $x$

STEP 2

We start with the given equation and isolate $H$ on one side of the equation.
$v=\frac{7}{4} A H$

STEP 3

To isolate $H$ , we divide both sides of the equation by $\frac{7}{} A$ .
$H=\frac{v}{\frac{7}{} A}$

STEP 4

To simplify the equation, we can multiply the denominator by the reciprocal of $\frac{7}{4}$ , which is $\frac{4}{7}$ .
$H=\frac{v}{A} \cdot \frac{4}{7}$

STEP 5

Now, the equation is in the form $H=x \frac{v}{A}$ , where $x$ is a constant. We can see that $x=\frac{4}{7}$ .
So, the value of $x$ is $\frac{4}{7}$ .

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QuestionFind the constant $x$ in the equation $H=x \frac{v}{A}$ from $v=\frac{7}{4} A H$ .

Studdy Solution

STEP 1

Assumptions1. The volume of the figure is given by the equation $v=\frac{7}{4} A H$ . The equation can be rewritten in the form $H=x \frac{v}{A}$ , where $x$ is a constant3. We need to find the value of $x$

STEP 2

We start with the given equation and isolate $H$ on one side of the equation.
$v=\frac{7}{4} A H$

STEP 3

To isolate $H$ , we divide both sides of the equation by $\frac{7}{} A$ .
$H=\frac{v}{\frac{7}{} A}$

STEP 4

To simplify the equation, we can multiply the denominator by the reciprocal of $\frac{7}{4}$ , which is $\frac{4}{7}$ .
$H=\frac{v}{A} \cdot \frac{4}{7}$

STEP 5

Now, the equation is in the form $H=x \frac{v}{A}$ , where $x$ is a constant. We can see that $x=\frac{4}{7}$ .
So, the value of $x$ is $\frac{4}{7}$ .

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QuestionFind the constant xxx in the equation H=xvAH=x \frac{v}{A}H=xAv​ from v=74AHv=\frac{7}{4} A Hv=47​AH.

Studdy Solution

STEP 1

Assumptions1. The volume of the figure is given by the equation v=74AHv=\frac{7}{4} A Hv=47​AH . The equation can be rewritten in the form H=xvAH=x \frac{v}{A}H=xAv​, where xxx is a constant3. We need to find the value of xxx

STEP 2

We start with the given equation and isolate HHH on one side of the equation.v=74AHv=\frac{7}{4} A Hv=47​AH

STEP 3

To isolate HHH, we divide both sides of the equation by 7A\frac{7}{} A7​A.H=v7AH=\frac{v}{\frac{7}{} A}H=7​Av​

STEP 4

To simplify the equation, we can multiply the denominator by the reciprocal of 74\frac{7}{4}47​, which is 47\frac{4}{7}74​.H=vA⋅47H=\frac{v}{A} \cdot \frac{4}{7}H=Av​⋅74​

STEP 5

Now, the equation is in the form H=xvAH=x \frac{v}{A}H=xAv​, where xxx is a constant. We can see that x=47x=\frac{4}{7}x=74​.So, the value of xxx is 47\frac{4}{7}74​.

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QuestionFind the constant $x$ in the equation $H=x \frac{v}{A}$ from $v=\frac{7}{4} A H$ .

Assumptions1. The volume of the figure is given by the equation $v=\frac{7}{4} A H$ . The equation can be rewritten in the form $H=x \frac{v}{A}$ , where $x$ is a constant3. We need to find the value of $x$

We start with the given equation and isolate $H$ on one side of the equation.
$v=\frac{7}{4} A H$

To isolate $H$ , we divide both sides of the equation by $\frac{7}{} A$ .
$H=\frac{v}{\frac{7}{} A}$

To simplify the equation, we can multiply the denominator by the reciprocal of $\frac{7}{4}$ , which is $\frac{4}{7}$ .
$H=\frac{v}{A} \cdot \frac{4}{7}$

Now, the equation is in the form $H=x \frac{v}{A}$ , where $x$ is a constant. We can see that $x=\frac{4}{7}$ .
So, the value of $x$ is $\frac{4}{7}$ .