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QuestionA freight elevator starts with 15,893 lbs, adds 3,473 lbs, then removes 5,492 lbs. Find the weight ww using the right equation.
Options: w=15,893−3,473+5,492w=15,893-3,473+5,492 w=15,893−3,473−5,492w=15,893-3,473-5,492 w=15,893+3,473−5,492w=15,893+3,473-5,492 w=15,893+3,473+5,492w=15,893+3,473+5,492

Studdy Solution

STEP 1

Assumptions1. The initial weight of the merchandise on the elevator is15,893 pounds. . An additional weight of3,473 pounds is added to the elevator.
3. A container weighing5,492 pounds is removed from the elevator.
4. The weight that the elevator is holding is represented by ww.

STEP 2

First, we need to understand the problem. The weight on the elevator initially is15,893 pounds. Then, an additional weight of,473 pounds is added to the elevator. After that, a container weighing5,492 pounds is removed from the elevator. We need to find an equation that correctly represents this situation.

STEP 3

The initial weight on the elevator is added to the additional weight put on the elevator. This is represented by the equationw=15,893+3,473w =15,893 +3,473

STEP 4

Next, the weight of the container that is removed from the elevator is subtracted from the total weight on the elevator. This is represented by the equationw=(15,893+3,473)−,492w = (15,893 +3,473) -,492

STEP 5

This equation can be simplified tow=15,893+3,473−5,492w =15,893 +3,473 -5,492So, the correct equation that could be used to solve for the amount of weight the freight elevator is holding after the container is taken off of it isw=15,893+3,473−5,492w =15,893 +3,473 -5,492

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