Math

QuestionFind the 8th term of the geometric sequence given by an=6(2)(n1)a_{n}=6 \cdot(-2)^{(n-1)}. Options: A. -768 B. 768 C. -1536 D. 1536

Studdy Solution

STEP 1

Assumptions1. The explicit formula for the geometric sequence is given by an=6()(n1)a_{n}=6 \cdot(-)^{(n-1)} . We need to find the8th term of the sequence, i.e., a8a_{8}

STEP 2

To find the8th term of the sequence, we substitute n=8n=8 into the explicit formula.
a8=6(2)(81)a_{8}=6 \cdot(-2)^{(8-1)}

STEP 3

implify the exponent in the formula.
a8=6(2)7a_{8}=6 \cdot(-2)^{7}

STEP 4

Calculate the value of (2)7(-2)^{7}.
(2)7=128(-2)^{7} = -128

STEP 5

Substitute the calculated value back into the formula to find a8a_{8}.
a8=(128)a_{8}= \cdot(-128)

STEP 6

Calculate the value of a8a_{8}.
a8=6(128)=768a_{8}=6 \cdot(-128) = -768So, the8th term of the geometric sequence is -768.

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