Math Snap

STEP 1

Assumptions1. Lead(IV) means that lead has a charge of +4.
. Iodine is a halogen and usually forms a -1 ion.
3. Selenium is a chalcogen and usually forms a - ion.
4. The compound formed between these elements is neutral, meaning the total positive charge equals the total negative charge.

STEP 2

First, we need to balance the charges for the compound formed between lead(IV) and iodine. The charge on lead(IV) is +4 and the charge on iodine is -1.
$$b^{4+} + I^-$$

STEP 3

To balance the charges, we need iodine ions for each lead(IV) ion.
$$b$$So, the chemical formula for the compound formed between lead(IV) and iodine is Pb.

STEP 4

Next, we need to balance the charges for the compound formed between lead(IV) and selenium. The charge on lead(IV) is +4 and the charge on selenium is -2.
$$b^{4+} + Se^{2-}$$

To balance the charges, we need2 selenium ions for each lead(IV) ion.
$$bSe2$$So, the chemical formula for the compound formed between lead(IV) and selenium is PbSe2.