QuestionWhat are the chemical formulas for the compounds formed between lead(IV) and iodine, and lead(IV) and selenium?

Studdy Solution

STEP 1

Assumptions1. Lead(IV) means that lead has a charge of +4. . Iodine is a halogen and usually forms a -1 ion.
3. Selenium is a chalcogen and usually forms a - ion.
4. The compound formed between these elements is neutral, meaning the total positive charge equals the total negative charge.

STEP 2

First, we need to balance the charges for the compound formed between lead(IV) and iodine. The charge on lead(IV) is +4 and the charge on iodine is -1.
$b^{4+} + I^-$

STEP 3

To balance the charges, we need iodine ions for each lead(IV) ion.
$b$ So, the chemical formula for the compound formed between lead(IV) and iodine is Pb.

STEP 4

Next, we need to balance the charges for the compound formed between lead(IV) and selenium. The charge on lead(IV) is +4 and the charge on selenium is -2.
$b^{4+} + Se^{2-}$

STEP 5

To balance the charges, we need2 selenium ions for each lead(IV) ion.
$bSe2$ So, the chemical formula for the compound formed between lead(IV) and selenium is PbSe2.

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QuestionWhat are the chemical formulas for the compounds formed between lead(IV) and iodine, and lead(IV) and selenium?

Studdy Solution

STEP 1

Assumptions1. Lead(IV) means that lead has a charge of +4. . Iodine is a halogen and usually forms a -1 ion.
3. Selenium is a chalcogen and usually forms a - ion.
4. The compound formed between these elements is neutral, meaning the total positive charge equals the total negative charge.

STEP 2

First, we need to balance the charges for the compound formed between lead(IV) and iodine. The charge on lead(IV) is +4 and the charge on iodine is -1.
$b^{4+} + I^-$

STEP 3

To balance the charges, we need iodine ions for each lead(IV) ion.
$b$ So, the chemical formula for the compound formed between lead(IV) and iodine is Pb.

STEP 4

Next, we need to balance the charges for the compound formed between lead(IV) and selenium. The charge on lead(IV) is +4 and the charge on selenium is -2.
$b^{4+} + Se^{2-}$

STEP 5

To balance the charges, we need2 selenium ions for each lead(IV) ion.
$bSe2$ So, the chemical formula for the compound formed between lead(IV) and selenium is PbSe2.

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QuestionWhat are the chemical formulas for the compounds formed between lead(IV) and iodine, and lead(IV) and selenium?

Studdy Solution

STEP 1

Assumptions1. Lead(IV) means that lead has a charge of +4. . Iodine is a halogen and usually forms a -1 ion.3. Selenium is a chalcogen and usually forms a - ion.4. The compound formed between these elements is neutral, meaning the total positive charge equals the total negative charge.

STEP 2

First, we need to balance the charges for the compound formed between lead(IV) and iodine. The charge on lead(IV) is +4 and the charge on iodine is -1.b4++I−b^{4+} + I^-b4++I−

STEP 3

To balance the charges, we need iodine ions for each lead(IV) ion.bbbSo, the chemical formula for the compound formed between lead(IV) and iodine is Pb.

STEP 4

Next, we need to balance the charges for the compound formed between lead(IV) and selenium. The charge on lead(IV) is +4 and the charge on selenium is -2.b4++Se2−b^{4+} + Se^{2-}b4++Se2−

STEP 5

To balance the charges, we need2 selenium ions for each lead(IV) ion.bSe2bSe2bSe2So, the chemical formula for the compound formed between lead(IV) and selenium is PbSe2.

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Assumptions1. Lead(IV) means that lead has a charge of +4. . Iodine is a halogen and usually forms a -1 ion.
3. Selenium is a chalcogen and usually forms a - ion.
4. The compound formed between these elements is neutral, meaning the total positive charge equals the total negative charge.

First, we need to balance the charges for the compound formed between lead(IV) and iodine. The charge on lead(IV) is +4 and the charge on iodine is -1.
$b^{4+} + I^-$

To balance the charges, we need iodine ions for each lead(IV) ion.
$b$ So, the chemical formula for the compound formed between lead(IV) and iodine is Pb.

Next, we need to balance the charges for the compound formed between lead(IV) and selenium. The charge on lead(IV) is +4 and the charge on selenium is -2.
$b^{4+} + Se^{2-}$

To balance the charges, we need2 selenium ions for each lead(IV) ion.
$bSe2$ So, the chemical formula for the compound formed between lead(IV) and selenium is PbSe2.