Math

QuestionFind the inverse of the function f(x)=19x+2f(x)=\frac{1}{9} x+2.

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=19x+f(x)=\frac{1}{9} x+ . We are looking for the inverse of this function

STEP 2

To find the inverse of a function, we first replace f(x)f(x) with yy.
y=19x+2y = \frac{1}{9} x +2

STEP 3

Next, we switch the roles of xx and yy. This means we replace every xx with yy and every yy with xx.
x=19y+2x = \frac{1}{9} y +2

STEP 4

Now, we solve for yy to get the inverse function. First, subtract2 from both sides.
x2=19yx -2 = \frac{1}{9} y

STEP 5

To isolate yy, multiply both sides by9.
9(x2)=y9(x -2) = y

STEP 6

implify the equation to get the inverse function.
y=9x18y =9x -18

STEP 7

Finally, replace yy with f1(x)f^{-1}(x) to denote the inverse function.
f1(x)=9x18f^{-1}(x) =9x -18The inverse of the function f(x)=19x+2f(x)=\frac{1}{9} x+2 is f1(x)=9x18f^{-1}(x) =9x -18.

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