QuestionFind the value of $\frac{4 x-y}{2 y+x}$ for $x=3$ and $y=3$ . Options: -3, 1, 9, 18.

Studdy Solution

STEP 1

Assumptions1. The expression is $\frac{4 x-y}{ y+x}$ . The value of $x$ is33. The value of $y$ 3

STEP 2

We need to substitute the given values of $x$ and $y$ into the expression. $\frac{4 x-y}{2 y+x} = \frac{4()-}{2()+}$

STEP 3

Now, we simplify the expression in the numerator.
$\frac{(3)-3}{2(3)+3} = \frac{12-3}{2(3)+3}$

STEP 4

Further simplify the numerator.
$\frac{12-3}{2(3)+3} = \frac{9}{2(3)+3}$

STEP 5

Now, we simplify the expression in the denominator.
$\frac{9}{2(3)+3} = \frac{9}{+3}$

STEP 6

Further simplify the denominator.
$\frac{9}{6+3} = \frac{9}{9}$

STEP 7

Finally, we simplify the fraction.
$\frac{9}{9} =1$ So, the value of the expression $\frac{4 x-y}{2 y+x}$ when $x=3$ and $y=3$ is1.

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