Math  /  Algebra

QuestionWhich equation can be rewritten as x+4=x2x+4=x^{2} ? Assume x>0x>0
x+2=x\sqrt{x}+2=x
x+2=x\sqrt{x+2}=x x+4=x\sqrt{x+4}=x x2+16=x\sqrt{x^{2}+16}=x

Studdy Solution

STEP 1

1. We are given four equations and need to determine which one can be rewritten as x+4=x2 x + 4 = x^2 .
2. We assume x>0 x > 0 for all equations.
3. We need to manipulate each equation to see if it can be transformed into x+4=x2 x + 4 = x^2 .

STEP 2

1. Analyze each equation individually.
2. Transform each equation to see if it matches x+4=x2 x + 4 = x^2 .
3. Identify the correct equation.

STEP 3

Analyze the first equation: x+2=x\sqrt{x} + 2 = x.
Subtract 2 from both sides:
x=x2 \sqrt{x} = x - 2
Square both sides to eliminate the square root:
x=(x2)2 x = (x - 2)^2
Expand the right side:
x=x24x+4 x = x^2 - 4x + 4
Rearrange to compare with x+4=x2 x + 4 = x^2 :
x25x+4=0 x^2 - 5x + 4 = 0
This does not match x+4=x2 x + 4 = x^2 .

STEP 4

Analyze the second equation: x+2=x\sqrt{x+2} = x.
Square both sides to eliminate the square root:
x+2=x2 x + 2 = x^2
This matches the form x+4=x2 x + 4 = x^2 if we adjust the constant term.

STEP 5

Analyze the third equation: x+4=x\sqrt{x+4} = x.
Square both sides to eliminate the square root:
x+4=x2 x + 4 = x^2
This matches the form x+4=x2 x + 4 = x^2 exactly.

STEP 6

Analyze the fourth equation: x2+16=x\sqrt{x^2 + 16} = x.
Square both sides to eliminate the square root:
x2+16=x2 x^2 + 16 = x^2
Subtract x2 x^2 from both sides:
16=0 16 = 0
This is not possible, so it does not match x+4=x2 x + 4 = x^2 .
The equation that can be rewritten as x+4=x2 x + 4 = x^2 is x+4=x\sqrt{x+4} = x.

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