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Math

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PROBLEM

Which expression equals logBADC\log \frac{B^{A}}{D^{C}}?
F. AClog(BD)A C \log (B-D)
G. AlogBClogDA \log B-C \log D
H. BlogA+DlogCB \log A+D \log C
J. BlogADlogCB \log A-D \log C
K. AlogB÷ClogDA \log B \div C \log D

STEP 1

Assumptions1. The logarithm is in base10.
. The variables A, B, C, and D represent real numbers.

STEP 2

We can use the properties of logarithms to simplify the given expression. The first property we will use is the quotient rule, which states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator.
logBAC=logBAlogDC\log \frac{B^{A}}{^{C}} = \log B^{A} - \log D^{C}

STEP 3

Next, we use the power rule of logarithms, which states that the logarithm of a number raised to an exponent is equal to the exponent times the logarithm of the number.
logBAlogDC=AlogBClogD\log B^{A} - \log D^{C} = A \log B - C \log D

SOLUTION

Now, we compare this expression with the given options. The expression AlogBClogDA \log B - C \log D matches with option G.
So, logBAC\log \frac{B^{A}}{^{C}} is equal to AlogBClogDA \log B - C \log D.

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