Math  /  Algebra

QuestionWhich statements are true? Check all that apply. The equation x4=8|-x-4|=8 will have two solutions. The equation 3.40.5x42.1=20.63.4|0.5 x-42.1|=-20.6 will have one solution. The equation 12x34=0\left|\frac{1}{2} x-\frac{3}{4}\right|=0 will have no solutions. The equation 2x10=20|2 x-10|=-20 will have two solutions. The equation 0.5x0.75+4.6=0.25|0.5 x-0.75|+4.6=0.25 will have no solutions. The equation 18x1=5\left|\frac{1}{8} x-1\right|=5 will have infinitely many solutions.

Studdy Solution

STEP 1

1. Absolute value equations can have zero, one, two, or no solutions depending on the equation.
2. An absolute value equation of the form A=B |A| = B has solutions if B0 B \geq 0 .
3. If B<0 B < 0 , the equation A=B |A| = B has no solutions.
4. If B=0 B = 0 , the equation A=B |A| = B has exactly one solution where A=0 A = 0 .

STEP 2

1. Analyze each equation individually to determine the number of solutions.
2. Apply the properties of absolute value equations to each statement.
3. Conclude which statements are true.

STEP 3

Analyze the equation x4=8 |-x-4|=8 :
The equation x4=8 |-x-4|=8 can be rewritten as two separate equations: x4=8orx4=8 -x-4 = 8 \quad \text{or} \quad -x-4 = -8
Solving these:
1. x4=8-x-4 = 8 leads to x=12 -x = 12 and thus x=12 x = -12 .
2. x4=8-x-4 = -8 leads to x=4 -x = -4 and thus x=4 x = 4 .

This equation has two solutions: x=12 x = -12 and x=4 x = 4 .

STEP 4

Analyze the equation 3.40.5x42.1=20.6 3.4|0.5 x-42.1|=-20.6 :
The absolute value equation 3.40.5x42.1=20.6 3.4|0.5 x-42.1|=-20.6 has a negative value on the right side. Since absolute values cannot be negative, this equation has no solutions.

STEP 5

Analyze the equation 12x34=0 \left|\frac{1}{2} x-\frac{3}{4}\right|=0 :
The equation 12x34=0 \left|\frac{1}{2} x-\frac{3}{4}\right|=0 implies that the expression inside the absolute value must be zero: 12x34=0 \frac{1}{2} x - \frac{3}{4} = 0
Solving for x x : 12x=34 \frac{1}{2} x = \frac{3}{4} x=34×2=32 x = \frac{3}{4} \times 2 = \frac{3}{2}
This equation has exactly one solution: x=32 x = \frac{3}{2} .

STEP 6

Analyze the equation 2x10=20 |2 x-10|=-20 :
The absolute value equation 2x10=20 |2 x-10|=-20 has a negative value on the right side. Since absolute values cannot be negative, this equation has no solutions.

STEP 7

Analyze the equation 0.5x0.75+4.6=0.25 |0.5 x-0.75|+4.6=0.25 :
First, isolate the absolute value: 0.5x0.75=0.254.6 |0.5 x-0.75| = 0.25 - 4.6 0.5x0.75=4.35 |0.5 x-0.75| = -4.35
The absolute value equation has a negative value on the right side. Since absolute values cannot be negative, this equation has no solutions.

STEP 8

Analyze the equation 18x1=5 \left|\frac{1}{8} x-1\right|=5 :
The equation 18x1=5 \left|\frac{1}{8} x-1\right|=5 can be rewritten as two separate equations: 18x1=5or18x1=5 \frac{1}{8} x - 1 = 5 \quad \text{or} \quad \frac{1}{8} x - 1 = -5
Solving these:
1. 18x1=5\frac{1}{8} x - 1 = 5 leads to 18x=6 \frac{1}{8} x = 6 and thus x=48 x = 48 .
2. 18x1=5\frac{1}{8} x - 1 = -5 leads to 18x=4 \frac{1}{8} x = -4 and thus x=32 x = -32 .

This equation has two solutions: x=48 x = 48 and x=32 x = -32 .
Conclusion: - The equation x4=8 |-x-4|=8 will have two solutions. (True) - The equation 3.40.5x42.1=20.6 3.4|0.5 x-42.1|=-20.6 will have one solution. (False) - The equation 12x34=0 \left|\frac{1}{2} x-\frac{3}{4}\right|=0 will have no solutions. (False) - The equation 2x10=20 |2 x-10|=-20 will have two solutions. (False) - The equation 0.5x0.75+4.6=0.25 |0.5 x-0.75|+4.6=0.25 will have no solutions. (True) - The equation 18x1=5 \left|\frac{1}{8} x-1\right|=5 will have infinitely many solutions. (False)

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