Math

QuestionFind the prime factorization of 10 and list the factors in ascending order (e.g., 2×52 \times 5).

Studdy Solution

STEP 1

Assumptions1. The number we are factorizing is10. We are looking for prime factors, which are numbers that have only two distinct positive divisors1 and the number itself3. We need to order the factors from least to greatest

STEP 2

Let's start by finding the smallest prime number that can divide10. The smallest prime number is2.

STEP 3

Check if2 is a factor of10. We can do this by dividing10 by2.
10/2=510 /2 =5

STEP 4

Since10 is divisible by2, we can say that2 is a prime factor of10. Now, we are left with the number.

STEP 5

Check if5 is a prime number. A prime number has only two distinct positive divisors1 and the number itself.

STEP 6

Since5 has only two distinct positive divisors (1 and5), we can say that5 is a prime number.

STEP 7

So,5 is also a prime factor of10.

STEP 8

Now, we have found all the prime factors of10. They are2 and5.

STEP 9

Order the prime factors from least to greatest. In this case, the prime factors are already in order from least to greatest.
The prime factorization of is 2×52 \times5.

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