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QuestionSolve the equation x−43=12\frac{x-4}{3}=\frac{1}{2}.

Studdy Solution

STEP 1

Assumptions1. We are given the equation x−43=1\frac{x-4}{3}=\frac{1}{}. . We need to solve for xx.

STEP 2

To solve for xx, we first need to get rid of the denominator on the left side of the equation. We can do this by multiplying both sides of the equation by.
⋅x−4=⋅12 \cdot \frac{x-4}{} = \cdot \frac{1}{2}

STEP 3

On the left side of the equation, the3 in the numerator and the3 in the denominator cancel out. On the right side of the equation, we multiply3 by 12\frac{1}{2}.
x−=3⋅12x- =3 \cdot \frac{1}{2}

STEP 4

Calculate the right side of the equation.
x−4=1.x-4 =1.

STEP 5

Now, we need to isolate xx on one side of the equation. We can do this by adding4 to both sides of the equation.
x−4+4=1.5+4x-4 +4 =1.5 +4

STEP 6

On the left side of the equation, -4 and +4 cancel out. On the right side of the equation, we add1.5 and4.
x=1.5+4x =1.5 +4

STEP 7

Calculate the right side of the equation.
x=5.5x =5.5The solution to the equation x−43=12\frac{x-4}{3}=\frac{1}{2} is x=5.5x =5.5.

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