Math  /  Algebra

Questiony=3x+1;y=3 x+1 ; domain ={1,0,1}=\{-1,0,1\}

Studdy Solution

STEP 1

What is this asking? We need to find the range of yy when xx can only be -1, 0, or 1! Watch out! Don't mix up domain and range!
The domain is the set of allowed xx values, and the range is the set of yy values we get after plugging in the xx values.

STEP 2

1. Substitute xx values
2. Determine the range

STEP 3

Let's **kick things off** by plugging in x=1x = -1 into our equation: y=3x+1y = 3 \cdot x + 1.
So, y=3(1)+1=3+1=2y = 3 \cdot (-1) + 1 = -3 + 1 = -2.
When xx is **-1**, yy is **-2**!

STEP 4

Next up, let's **tackle** x=0x = 0.
Substituting into y=3x+1y = 3 \cdot x + 1, we get y=30+1=0+1=1y = 3 \cdot 0 + 1 = 0 + 1 = 1.
So, when xx is **0**, yy is **1**!

STEP 5

Finally, let's **wrap up** with x=1x = 1.
Plugging it into y=3x+1y = 3 \cdot x + 1, we have y=31+1=3+1=4y = 3 \cdot 1 + 1 = 3 + 1 = 4.
When xx is **1**, yy is **4**!

STEP 6

We found that when xx is -1, yy is -2.
When xx is 0, yy is 1.
And when xx is 1, yy is 4.

STEP 7

The range is simply all the possible yy values.
So, our range is {2,1,4}\{-2, 1, 4\}!

STEP 8

The range of the function y=3x+1y = 3x + 1 with domain {1,0,1}\{-1, 0, 1\} is {2,1,4}\{-2, 1, 4\}.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord