Math

QuestionYolanda bought 3×(14+78+112)3 \times\left(\frac{1}{4}+\frac{7}{8}+1 \frac{1}{2}\right) lbs and Sam bought 2×(14+78+112)2 \times\left(\frac{1}{4}+\frac{7}{8}+1 \frac{1}{2}\right) lbs. Who bought more? Explain.

Studdy Solution

STEP 1

Assumptions1. Yolanda bought 3×(14+78+11)3 \times\left(\frac{1}{4}+\frac{7}{8}+1 \frac{1}{}\right) pounds of cheese. . Sam bought ×(14+78+11) \times\left(\frac{1}{4}+\frac{7}{8}+1 \frac{1}{}\right) pounds of cheese.
3. We need to determine who bought more cheese without doing any calculations.

STEP 2

We can see that the quantities of cheese that Yolanda and Sam bought are multiples of the same quantity (14+78+112)\left(\frac{1}{4}+\frac{7}{8}+1 \frac{1}{2}\right).

STEP 3

Yolanda bought3 times the quantity (1+78+112)\left(\frac{1}{}+\frac{7}{8}+1 \frac{1}{2}\right), while Sam bought2 times the same quantity.

STEP 4

Since3 is greater than2, we can conclude that Yolanda bought more cheese than Sam without doing any calculations.
Yolanda bought more cheese than Sam.

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