Math  /  Numbers & Operations

Question32+32\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}

Studdy Solution

STEP 1

What is this asking? We're adding two identical square roots!
How simple is that?! Watch out! Don't accidentally multiply the square roots.
We are *adding* them.

STEP 2

1. Simplify the expression

STEP 3

We have two identical terms, both equal to 32\frac{\sqrt{3}}{2}, and we're adding them together.
We can rewrite this as a multiplication!
This is like saying "one apple plus one apple" is the same as "two apples." So, we have:
32+32=232 \frac{\sqrt{3}}{2} + \frac{\sqrt{3}}{2} = 2 \cdot \frac{\sqrt{3}}{2}

STEP 4

We're multiplying 22 by the fraction 32\frac{\sqrt{3}}{2}.
Remember that 22 is really 21\frac{2}{1}, so we have:
232=2132 2 \cdot \frac{\sqrt{3}}{2} = \frac{2}{1} \cdot \frac{\sqrt{3}}{2}

STEP 5

When multiplying fractions, we multiply the **numerators** together and the **denominators** together.
Let's do it:
2132=2312 \frac{2}{1} \cdot \frac{\sqrt{3}}{2} = \frac{2 \cdot \sqrt{3}}{1 \cdot 2}

STEP 6

Look at the fraction 2312\frac{2 \cdot \sqrt{3}}{1 \cdot 2}.
Both the numerator and the denominator have a factor of **2**.
We can divide both the numerator and denominator by 2\bf{2} to simplify the fraction.
Remember that dividing by 22 is the same as multiplying by 12\frac{1}{2}, so we have:
2321212=131 \frac{2 \cdot \sqrt{3}}{2} \cdot \frac{\frac{1}{2}}{\frac{1}{2}} = \frac{1 \cdot \sqrt{3}}{1}

STEP 7

Anything divided by 11 is just itself, so we have:
131=3 \frac{1 \cdot \sqrt{3}}{1} = \sqrt{3}

STEP 8

Our **final answer** is 3\sqrt{3}!

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