Math  /  Algebra

Question4c7c+2c2\frac{\frac{4}{c}}{\frac{7}{c}+\frac{2}{c^{2}}}

Studdy Solution

STEP 1

1. We need to simplify the given complex fraction.
2. The variable c c is non-zero to avoid division by zero.
3. The expression can be simplified by finding a common denominator.

STEP 2

1. Simplify the denominator of the complex fraction.
2. Simplify the entire complex fraction.

STEP 3

Identify the common denominator in the denominator of the complex fraction:
The denominator is 7c+2c2\frac{7}{c} + \frac{2}{c^2}.
The common denominator for 7c\frac{7}{c} and 2c2\frac{2}{c^2} is c2c^2.
Rewrite each term with the common denominator:
7c=7cc2 \frac{7}{c} = \frac{7c}{c^2}
2c2=2c2 \frac{2}{c^2} = \frac{2}{c^2}
Combine the terms:
7cc2+2c2=7c+2c2 \frac{7c}{c^2} + \frac{2}{c^2} = \frac{7c + 2}{c^2}

STEP 4

Simplify the entire complex fraction:
The original expression is:
4c7c+2c2 \frac{\frac{4}{c}}{\frac{7}{c} + \frac{2}{c^2}}
Substitute the simplified denominator:
4c7c+2c2 \frac{\frac{4}{c}}{\frac{7c + 2}{c^2}}
Simplify by multiplying by the reciprocal of the denominator:
4c×c27c+2 \frac{4}{c} \times \frac{c^2}{7c + 2}
Cancel the common factor c c in the numerator and denominator:
4c7c+2 \frac{4c}{7c + 2}
The simplified expression is:
4c7c+2 \frac{4c}{7c + 2}

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