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Math  /  Numbers & Operations

Questiong. 28,000÷4028,000 \div 40

Studdy Solution

STEP 1

What is this asking? How many times does 40 go into 28,000?
Think of it like dividing $28,000\$28,000 equally among **40 friends**! Watch out! Keep your place values straight!
A misplaced zero can lead to a *wildly* different answer.

STEP 2

1. Simplify the Problem
2. Perform the Division

STEP 3

We've got a big number there, $28,000\$28,000!
Let's make it a bit easier to handle.
We can simplify the problem by noticing that both $28,000\$28,000 and **40** have a common factor of **10**.
Dividing both numbers by **10** gives us 28002800 and **4**, respectively.
This makes our division much simpler!
We're essentially removing a zero from each number.
Why can we do this?
Because dividing both the **numerator** (28,00028,000) and the **denominator** (40) by the same number (10) is like dividing by one, which doesn't change the *value* of the overall expression.
It's like simplifying a fraction!

STEP 4

So, our new problem is 2800÷42800 \div 4.
This is *much* friendlier!

STEP 5

Let's break down the division.
How many times does **4** go into **28**?
Well, 4⋅7=284 \cdot 7 = 28, so it goes in **7** times perfectly!

STEP 6

Now, we're left with those two zeros in **28**00.
Since **4** goes into **28** exactly **7** times, **4** goes into **2800** exactly **700** times.
We just add those two zeros back on!
So, 2800÷4=7002800 \div 4 = 700.

STEP 7

So, $28,000÷40=$700\$28,000 \div 40 = \$700.
Each of your **40 friends** gets $700\$700!

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