Math  /  Algebra

Question4. The ratio of "D"s to "A"s in the school was 8 to 21 . If there were 572 As in the school this term, how many Ds were there? 1502 304 218 1762

Studdy Solution
Solve the proportion. Cross-multiply to solve for D D :
21D=8×572 21D = 8 \times 572
Calculate the right-hand side:
21D=4576 21D = 4576
Divide both sides by 21 to isolate D D :
D=457621 D = \frac{4576}{21}
Calculate the division:
D=218 D = 218
The number of "D"s is:
218 \boxed{218}

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