Math  /  Geometry

QuestionProve that for ABC\triangle ABC with external angle ACD\angle ACD, mACD=mB+mAm \angle ACD = m \angle B + m \angle A.

Studdy Solution
The first statement is given as a fact, so the reason for this statement is "Given".Reason for ABC with external angle, ACD="Given"\text{Reason for } \triangle A B C \text{ with external angle, } \angle A C D = \text{"Given"}

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