QuestionConsider the following binomial probability distribution expression below. The number of trials, the number of successes, the probability of success and the probability of failure respectively are: $$\binom{12}{7}(0.1)^{7}(0.9)^{5}$$ $7,0.1,0.9,12$ $12,7,0.1,0.9$ $12,7,0.9,0.1$ $7,0.9,12,0.1$