Math  /  Data & Statistics

QuestionEvaluate the following formula for xˉ1=27.6106,xˉ2=25.9487,μ1μ2=0,s1=43.83,s2=43.83,n1=40\bar{x}_{1}=27.6106, \bar{x}_{2}=25.9487, \mu_{1}-\mu_{2}=0, s_{1}=43.83, s_{2}=43.83, n_{1}=40, and n2=43n_{2}=43. t=(xˉ1xˉ2)(μ1μ2)s12n1+s22n2t=\frac{\left(\bar{x}_{1}-\bar{x}_{2}\right)-\left(\mu_{1}-\mu_{2}\right)}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}} t=t= \square (Round to two decimal places as needed.)

Studdy Solution
Evaluate the formula:
t=1.66199.63040.1725t = \frac{1.6619}{9.6304} \approx 0.1725
Round to two decimal places:
t0.17t \approx 0.17
The value of t t is:
0.17 \boxed{0.17}

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