QuestionFind the equation of the line that is perpendicular to the line $4 x-8 y=7$ and passes through the point $(1,1)$. $$y=-2 x+3$$

Studdy Solution
Simplify the equation from the point-slope form to the slope-intercept form.
$$y - 1 = -2(x - 1)$$ $$y - 1 = -2x + 2$$ $$y = -2x + 3$$
Therefore, the equation of the line that is perpendicular to $4x - 8y = 7$ and passes through the point $(1,1)$ is:
$$y = -2x + 3$$