Math  /  Word Problems

QuestionCalculate moles of ethanol needed for 0.085 mol of acetic acid from the reaction: C2H5OH+O2H2O+CH3COOH\mathrm{C_2H_5OH} + \mathrm{O_2} \rightarrow \mathrm{H_2O} + \mathrm{CH_3COOH}.

Studdy Solution
Since the ratio of ethanol to acetic acid is11, the moles of ethanol needed to produce0.085 mol of acetic acid is also0.085 mol.
The solution is0.085 mol of ethanol.

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